Mass of ethylene = 45.0 g
Molar mass of ethylene = 28.05 g/mol
The formula for the calculation of moles is shown below:
According to the reaction below:-
1 mole of ethylene produces 2 moles of carbon dioxide
1.60 mole of ethylene produces 2*1.60 moles of carbon dioxide
Moles of carbon dioxide = 3.2 mol
Molar mass of carbon dioxide = 44.01 g/mol
Mass = Moles*Molar mass = 3.2 mol x 44.01 g/mol = 141 g
D.141 g of carbon dioxide will be produced
Here, a solution of Fe(NO₃)₃ is diluted, as the total volume of the solution has increased. The formula for dilution of the compound is mathematically expressed as:
Here, C and V are the concentration and volume respectively. The numbers at the subscript denote the initial and final values. The concentration of Fe(NO₃)₃ is 1.75 M. As ferric nitrate dissociates completely in water, the initial concentration of ferric is also 1.75 M.
Solving for [Fe],
There are three moles of nitrate is 1 mole of Fe(NO₃)₃. This means that the initial concentration of nitrate ions will be three times the concentration of ferric nitrate i.e., it will be 5.25 M.
From the question we are given;
We are required to determine the new volume of the gas;
We are going to use Boyle's law of gases.
At different pressures and volume with constant temperature, then
Rearranging the formula;
Thus, the new volume of the gas is 187.5 mL
At STP, 1 mole of ideal gas has a volume of 22.4 liters.
Therefore, since liters and moles are directly proportional, we can use stoichiometry directly.
40L CH₄ × (2L H₂ / 1L CH₄) = 80L H₂
Vb = 18 L option c)
First, we need to write the titration reaction between the base and the acic, which is the following:
Ba(OH)₂ + H₃PO₄ <-------> Ba₃(PO₄)₂ + H₂O
However this equation is not balanced, we need to balance the equation adding some coefficients to the agents so:
3Ba(OH)₂ + 2H₃PO₄ <-------> Ba₃(PO₄)₂ + 6H₂O
Now that the equation is balanced, as we know this is an acid base titration, we need to calculate the mole ratio between the base and acid so:
moles B / moles A = 3/2
2 moles B = 3 moles A (1)
This is taken from the balanced reaction.
Now, finally we use the relation in titration which is:
moles A = moles B
or simply MaVa = MbVb
If we replace this in the ratio of this reaction we have:
2MbVb = 3MaVa (2)
And from there, we solve for Vb which is the volume of the base:
2 * 2 * Vb = 3 * 4 * 6
4Vb = 72
Vb = 72/4
Vb = 18 L
This is the volume of the base required to titrate this acid
Prokaryotes and eukaryotes use the same codons for translation.
Gene is the functional segment of the DNA and can be inherited. The particular gene codes for the particular protein that determines the morphology of the organisms.
The translation process is responsible for the expression of protein in prokaryotes and eukaryotes. The basic process of translation is quite similar. Genetic code is same in both prokaryotes and eukaryotes as the code is universal in nature and responsible for the production of protein in bacteria.
Consider this statement as True or false
Yes, it is possible that the gene responsible for the fluroscence in the jelly fish is extracted and inserted in the bacteria then the bacteria will also start glowing like jellyfish.
This is possible because the basic machinery is same in case of prokaryotes and eukaryotes.
The manipulation is known as genetic engineering by which the gene of interest from one organism is inserted in other organism.
The new total body concentration would be 300 mOsM
In order to do this, we need to convert all concentrations to moles.
First, with the total body concentration, we have the initial volume of 3 liters and the concentration of 300 M (I will omit til the end the part of mOs)
The moles of the body concentration in this volume is:
moles = M * V
moles = 300 * 3 = 900 moles
To this moles, we add 150 moles of NaCL so, the total moles now is:
moles = 900 + 150 = 1050 moles
Finally, we can calculate the concentration with the new volume of 3.5 L (the sum of 3 and 0.5 liters added):
M = 1050 / 3.5
M = 300 mOsM
So the concentration remains the same as initial
The molar Heat of fusion based on the mass of iron and the heat released is 2756.3 cal/mol
The heat absorbed by one mole of a substance when it changes from a solid to a liquid is known as the molar heat of fusion (ΔHfus) of that substance. Any substance that melts absorbs heat, thus it seems sensible that a substance that freezes would release heat.
The molar heat of fusion is calculated as follows:
Heat change = moles * molar heat of fusion
moles of iron = mass / molar mass
molar mass of iron = 56 g/mol
mass of iron = 200 g
moles of iron = 200 / 56
moles of iron = 3.57 moles
Molar Heat of fusion = heat change / moles of iron
Molar Heat of fusion = 9840 / 3.57
Molar Heat of fusion = 2756.3 cal/mol
Learn more about molar heat of fusion at: brainly.com/question/29524112
The correct answer is that we need three fluoride ions (F-1) to balance the compound.
Let's solve this!
For the compound to be balanced, the charges have to be balanced.
We have +3 loads of Al and -1 of F.
We must multiply by 3 the Fluor so that it is as follows:
+ 3 + 3 * (- 1) = + 3-3 = 0
Therefore, we conclude that the correct answer is that we need three fluoride ions (F-1) to balance the compound.
Freezing point depends on relative molecular mass and nature of intermolecular forces. In glycerin, the relative molecular is the least of the the molecules are held together only by weak Vanderwaals forces. Phenol has stronger dipole interactions and higher relative molecular mass. Potassium bromide is ionic and posses very strong bonds hence it has the highest freezing point.